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CGP EDU Academic Team
Published on: September 12, 2026
Two charges each equal to $2 \mu C$ are 0.5m apart. If both of them exist inside vacuum, then the force between them is
Text Solution
Verified by ExpertsThe correct answer is:
C
By using $F = 9 \times 10^{9} \cdot \frac{Q^{2}}{r^{2}}$
⇒ ⇒ $F = 9 \times 10^{9} \cdot \frac{\left(2 \times 10^{-6}\right)^{2}}{(0.5)^{2}} = 0.144 N$
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